leetcode-155-min-stack

Description

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

  • push(x) – Push element x onto stack.
  • pop() – Removes the element on top of the stack.
  • top() – Get the top element.
  • getMin() – Retrieve the minimum element in the stack.

Example:

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MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> Returns -3.
minStack.pop();
minStack.top(); --> Returns 0.
minStack.getMin(); --> Returns -2.

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class MinStack {
class MinNode{
int min, val;
public MinNode(int min, int val){
this.min = min;
this.val = val;
}
}

Stack<MinNode> st;
int min;
public MinStack() {
st = new Stack<MinNode>();
min = Integer.MAX_VALUE;
}

public void push(int x) {
if(x <= min) min = x;
MinNode t = new MinNode(min, x);
st.push(t);
}

public void pop() {
if(!st.isEmpty()){
MinNode t = st.pop();

//need to reset the min to what it was before we saw this value
if(!st.isEmpty()) min = st.peek().min;
else min = Integer.MAX_VALUE;
}
}

public int top() {
if(st.isEmpty()) return -1;
return st.peek().val;
}

public int getMin() {
if(st.isEmpty()) return -1;
return st.peek().min;
}
}
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