习题11-8 单链表结点删除（20 分）
本题要求实现两个函数，分别将读入的数据存储为单链表、将链表中所有存储了某给定值的结点删除。链表结点定义如下：
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| struct ListNode {
int data;
ListNode *next;
};
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函数接口定义：
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| struct ListNode *readlist();
struct ListNode *deletem( struct ListNode *L, int m );
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函数readlist从标准输入读入一系列正整数，按照读入顺序建立单链表。当读到−1时表示输入结束，函数应返回指向单链表头结点的指针。
函数deletem将单链表L中所有存储了m的结点删除。返回指向结果链表头结点的指针。
裁判测试程序样例：
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| #include <stdio.h>
#include <stdlib.h>
struct ListNode {
int data;
struct ListNode *next;
};
struct ListNode *readlist();
struct ListNode *deletem( struct ListNode *L, int m );
void printlist( struct ListNode *L )
{
struct ListNode *p = L;
while (p) {
printf("%d ", p->data);
p = p->next;
}
printf("\n");
}
int main()
{
int m;
struct ListNode *L = readlist();
scanf("%d", &m);
L = deletem(L, m);
printlist(L);
return 0;
}
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输入样例：
输出样例：
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| #include <stdio.h>
#include <stdlib.h>
struct ListNode {
int data;
struct ListNode *next;
};
struct ListNode *readlist();
struct ListNode *deletem( struct ListNode *L, int m );
void printlist( struct ListNode *L )
{
struct ListNode *p = L;
while (p) {
printf("%d ", p->data);
p = p->next;
}
printf("\n");
}
int main()
{
int m;
struct ListNode *L = readlist();
scanf("%d", &m);
L = deletem(L, m);
printlist(L);
return 0;
}
void PushBack(int X, struct ListNode **rear)
{
struct ListNode *TmpCell;
TmpCell = malloc(sizeof(struct ListNode));
TmpCell->data = X;
TmpCell->next = NULL;
(*rear)->next = TmpCell;
*rear = TmpCell;
}
struct ListNode *readlist()
{
struct ListNode *TmpCell, *head, *tail;
int data;
head = tail = malloc(sizeof(struct ListNode));
head->next = NULL;
scanf("%d", &data);
while (data != -1) {
PushBack(data, &tail);
scanf("%d", &data);
}
TmpCell = head;
head = head->next;
free(TmpCell);
return head;
}
struct ListNode *deletem(struct ListNode *L, int m)
{
struct ListNode *head, *p, *TmpCell;
p = head = malloc(sizeof(struct ListNode));
head->next = NULL;
p->next = L;
while (p->next != NULL) {
if (p->next->data == m) {
TmpCell = p->next;
p->next = TmpCell->next;
free(TmpCell);
} else
p = p->next;
}
TmpCell = head;
head = head->next;
free(TmpCell);
return head;
}
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